Question

In: Statistics and Probability

Callahan (2009) demonstrated that Tai Chi can significantly reduce symptoms for individuals with arthritis. Participants were...

Callahan (2009) demonstrated that Tai Chi can significantly reduce symptoms for individuals with arthritis. Participants were 18 years old or older with doctor-diagnosed arthritis. Self-reports of pain and stiffness were measured at the beginning of an 8-week Tai Chi course and again at the end. Supposed that the data produced an average decrease in pain and stiffness of MD=7.5 points with a standard deviation of 20.5 for a sample of n=40 participants
a.) Use a two-tailed test with alpha =.05 to determine whether the tai chi had a significant effect on pain and stiffness.

b.) compute Cohen's D to measure the size of the treatment effect.

Solutions

Expert Solution

a)

mean of difference ,    D̅ =    7.500                  
                          
std dev of difference , Sd =        20.5000                  
                          
std error , SE = Sd / √n =    20.5000   / √   40   =   3.2413      
                          
t-statistic = (D̅ - µd)/SE = (   7.5   -   0   ) /    3.2413   =   2.314
                          
Degree of freedom, DF=   n - 1 =    39                  
t-critical value , t* =    ±   2.0227   [excel function: =t.inv.2t(α,df) ]               
                          
p-value =        0.0260   [excel function: =t.dist.2t(t-stat,df) ]               
Decision:   p-value <α , Reject null hypothesis                      

b)

  
cohen's d = |Dbar/ std dev| =    0.37


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