In: Statistics and Probability
Callahan (2009) demonstrated that Tai Chi can significantly
reduce symptoms for individuals with arthritis. Participants were
18 years old or older with doctor-diagnosed arthritis. Self-reports
of pain and stiffness were measured at the beginning of an 8-week
Tai Chi course and again at the end. Supposed that the data
produced an average decrease in pain and stiffness of MD=7.5 points
with a standard deviation of 20.5 for a sample of n=40
participants
a.) Use a two-tailed test with alpha =.05 to determine whether the
tai chi had a significant effect on pain and stiffness.
b.) compute Cohen's D to measure the size of the treatment effect.
a)
mean of difference , D̅ =
7.500
std dev of difference , Sd =
20.5000
std error , SE = Sd / √n = 20.5000 /
√ 40 = 3.2413
t-statistic = (D̅ - µd)/SE = ( 7.5
- 0 ) / 3.2413
= 2.314
Degree of freedom, DF= n - 1 =
39
t-critical value , t* = ±
2.0227 [excel function: =t.inv.2t(α,df) ]
p-value =
0.0260 [excel function: =t.dist.2t(t-stat,df)
]
Decision: p-value <α , Reject null
hypothesis
b)
cohen's d = |Dbar/ std dev| = 0.37