y"´-9y"+26y´-24y=1 y(0)=y´(0)=y"(0)=1

Expert Solution

Colby Messinger answered 11 months ago

Find the exact solution : y''+9y'=cosπt, y(0)=0,y'(0）=1

Find y as a function of t if 100y′′−9y=0100y″−9y=0 with y(0)=3,y′(0)=8.

(1 point) Find yy as a function of xx if y‴+9y′=0,y‴+9y′=0, y(0)=−2, y′(0)=24, y″(0)=−18.y(0)=−2, y′(0)=24, y″(0)=−18. y(x)= ?

Solve by variation of parameters: A. y"−9y = 1/(1 − e^(3t)) B. y" +2y'+26y = e^-t/sin(5t)

ﬁnd the general solution of the given differential equation. 1. y''+2y'−3y=0 2. 6y''−y'−y=0 3. y''+5y' =0 4. y''−9y'+9y=0

u''-2u'-8u=0 u(0)= α， u'(0)=2π y''+9y'=cosπt, y(0)=0, y'(0)=1

Solve the laplace transform to solve the initial value problem. y"-6y'+9y=t. Y(0)=0, y'(0)=1

y″+9y′=162sin(9t)+324cos(9t) y(0)=7 y'(0)=7

1) Find y as a function of t if 9y′′+24y′+32y=0, y(0)=5,y′(0)=8. y(t)= 2) Find y as...

1) Find y as a function of t if 9y′′+24y′+32y=0, y(0)=5,y′(0)=8. y(t)= 2) Find y as a function of x if y′′′+16y′=0, y(0)=−5, y′(0)=−32, y′′(0)=−32. y(x)= 3) Find y as a function of t if 9y′′−12y′+40y=0, y(1)=5,y′(1)=9. y=

Question

y"´-9y"+26y´-24y=1 y(0)=y´(0)=y"(0)=1

Solutions

Expert Solution

Related Solutions

Find the exact solution : y''+9y'=cosπt, y(0)=0,y'(0）=1

Find the exact solution : y''+9y'=cosπt, y(0)=0,y'(0）=1

Find y as a function of t if 100y′′−9y=0100y″−9y=0 with y(0)=3,y′(0)=8.

(1 point) Find yy as a function of xx if y‴+9y′=0,y‴+9y′=0, y(0)=−2, y′(0)=24, y″(0)=−18.y(0)=−2, y′(0)=24, y″(0)=−18. y(x)= ?

Solve by variation of parameters: A. y"−9y = 1/(1 − e^(3t)) B. y" +2y'+26y = e^-t/sin(5t)

ﬁnd the general solution of the given differential equation. 1. y''+2y'−3y=0 2. 6y''−y'−y=0 3. y''+5y' =0 4. y''−9y'+9y=0

u''-2u'-8u=0 u(0)= α， u'(0)=2π y''+9y'=cosπt, y(0)=0, y'(0)=1

Solve the laplace transform to solve the initial value problem. y"-6y'+9y=t. Y(0)=0, y'(0)=1

y″+9y′=162sin(9t)+324cos(9t) y(0)=7 y'(0)=7

1) Find y as a function of t if 9y′′+24y′+32y=0, y(0)=5,y′(0)=8. y(t)= 2) Find y as...