Find the exact solution : y''+9y'=cosπt, y(0)=0,y'(0）=1

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Colby Messinger answered 2 years ago

Find the exact solution : y''+9y'=cosπt, y(0)=0,y'(0）=1

Find y as a function of t if 100y′′−9y=0100y″−9y=0 with y(0)=3,y′(0)=8.

ﬁnd the general solution of the given differential equation. 1. y''+2y'−3y=0 2. 6y''−y'−y=0 3. y''+5y' =0 4. y''−9y'+9y=0

(1 point) Find yy as a function of xx if y‴+9y′=0,y‴+9y′=0, y(0)=−2, y′(0)=24, y″(0)=−18.y(0)=−2, y′(0)=24, y″(0)=−18. y(x)= ?

y"´-9y"+26y´-24y=1 y(0)=y´(0)=y"(0)=1

1) Find y as a function of t if 9y′′+24y′+32y=0, y(0)=5,y′(0)=8. y(t)= 2) Find y as...

1) Find y as a function of t if 9y′′+24y′+32y=0, y(0)=5,y′(0)=8. y(t)= 2) Find y as a function of x if y′′′+16y′=0, y(0)=−5, y′(0)=−32, y′′(0)=−32. y(x)= 3) Find y as a function of t if 9y′′−12y′+40y=0, y(1)=5,y′(1)=9. y=

Find the green's function then find the solution y"+4y=x y(0)=0, y'(1)=0

Find y as a function of x if y^(4)−6y′′′+9y′′=0, y(0)=7, y′(0)=11, y′′(0)=9, y′′′(0)=0.

In Exercises 1-20, find a general solution of the Cauchy-Euler equation. (Assume x > 0). (x^(2))y''-5xy'+9y=0

Find a particular solution to y''+6y'+9y=(-18.5e^(-3t))/(t^2+1)

Question

Find the exact solution : y''+9y'=cosπt, y(0)=0,y'(0）=1

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Find the exact solution : y''+9y'=cosπt, y(0)=0,y'(0）=1

Find y as a function of t if 100y′′−9y=0100y″−9y=0 with y(0)=3,y′(0)=8.

ﬁnd the general solution of the given differential equation. 1. y''+2y'−3y=0 2. 6y''−y'−y=0 3. y''+5y' =0 4. y''−9y'+9y=0

(1 point) Find yy as a function of xx if y‴+9y′=0,y‴+9y′=0, y(0)=−2, y′(0)=24, y″(0)=−18.y(0)=−2, y′(0)=24, y″(0)=−18. y(x)= ?

y"´-9y"+26y´-24y=1 y(0)=y´(0)=y"(0)=1

1) Find y as a function of t if 9y′′+24y′+32y=0, y(0)=5,y′(0)=8. y(t)= 2) Find y as...

Find the green's function then find the solution y"+4y=x y(0)=0, y'(1)=0

Find y as a function of x if y^(4)−6y′′′+9y′′=0, y(0)=7, y′(0)=11, y′′(0)=9, y′′′(0)=0.

In Exercises 1-20, find a general solution of the Cauchy-Euler equation. (Assume x > 0). (x^(2))y''-5xy'+9y=0

Find a particular solution to y''+6y'+9y=(-18.5e^(-3t))/(t^2+1)