Question

1) Ringer's injection contain 0.86% of sodium chloride, 0.03% of potassium chloride, and 0.033% of calcium chloride dihydrate. Calculate the sodium, potassium, calcium, and chloride content in mEq/L.

2). If a liter of an intravenous fluid contains 5% dextrose and 34 mEq sodium (as NaCl), calculate the percent strength of sodium chloride in the solution.

3). A flavored potassium chloride packet contains 1.5 g of potassium chloride. Hoe many milliequivalents of potassium chloride are represented in each packet?

4). How many milliequivalents of Li+ are provided by a daily dose of our 300 mg tablets of lithium carbonate (Li2CO2- MW 74).

34). A physician wishes to administer 1,200,000 units of penicillin G potassium every 4 hours. If 1 unit of penicillin G potassium (C16H17KN2O4S- mw. 372) equals 0.6 mcg, how many milliequivalents of K+ will the patient receive in a 24-hours period?

36). How many milligrams of magnesium sulfate (MgSO4. 120) should be added to an intravenous solution to provide 5 mEq of Mg2+ per liter? 41). A normal 70kg (154Ib) adult has 80 to 100g of sodium. It is primarily distributed in the extracellular fluid. Body retention of 1 g additional of sodium results in excess body water accumulation of approximately 310 mL. If a person retains 100mEq of extra sodium, how many milliliters of additional water could be expected to be retained?

44). The usual adult dose of calcium for elevating serium calcium is 7 to 14 mEq. How many milliliters of a calcium gluceptate injection, ech milliliter of which provides 18 mg of element calcium, would provide the recommended dosage range?

46) Calculate the milliequivalents of chloride per liter of the folllowing parenteral fluid: Sodium Chloride 516mg Potassium Chloride 89.4mg Calcium Chloride, anhyd 27.8 mg Magnesium chloride, anhyd 14.2 mg Sodium lactate, anhyd. 560mg Water for injection ad. 100mL

48). GOLYTELY, a colon lavage preparation, conatins the following mixture of dry powder in each packet to prepare one gallon of solution: Sodium sulfate 21.5g Sodium chloride 5.53g Potassium chloride 2.82g Sodium bicarbonate 6.36g Polyethylene glycol (3350) 227.1g

52). A solution contains 322 mg of Na+ ions per liter. How many milliosmoles are represented in the solution?

54). Calculate the osmolarity, in milliosmoles per liter, of a parenteral solution containing 2 mEq/mL of potassium acetate (KC2H3O2- mw 98).

57). A hospital medication order calls for the administration of 100g of mannitol to a patient as an osmotic diuretic over a 24-hours period. Calculate. a) how many milliliters of a 15% w/v mannitol injection should be administered per hour and b0 how many milliosmoles of mannnitol (mw 182) would be represented in the prescribed dosage.

Answer 1

Ringer's injection contain 0.86% of sodium chloride, 0.03% of potassium chloride, and 0.033% of calcium chloride dihydrate. Calculate the sodium, potassium, calcium, and chloride content in mEq/L.

Given that;

0.86% of sodium chloride,

0.03% of potassium chloride,

0.033% of calcium chloride dehydrate

Assume that the total amount of injection is 100 g

So here

NaCl = 0.86% or 0.86/100 g

KCl = 0.03% or 0.03/100 g

CaCl2 = 0.033% or 0.033/100 g

Now calculate the moles of all species:

Number of moles = amount in g/ molar mass

NaCl = 0.0086g / 58.44 g/mol

= 1.47*10^-4 mole NaCl

Or

1.47*10^-4 mole Na + and 1.47*10^-4 mole Cl-

KCl = 0.0003g / 74.5513 g/mol

= 4.02*10^-6 mole KCl

Or

4.02*10^-6 mole K + and 4.02*10^-6 mole Cl-

CaCl2 = 0.033% or 0.033/100 g

CaCl2 = 0.00033 g /110.98 g/mol

= 2.97*10^-6 mole CaCl2

Or

2.97*10^-6 mole Ca^2+

and 5.95*10^-6 mole Cl-

we know that; 1 millimole = 10^-3 moles.

Here

1.47*10^-4 mole Na + = 0.147 mmol Na+

1.47*10^-4 mole Cl- =0.147 mmol Cl-

4.02*10^-6 mole K + =4.02*10^-3 mmole K +

4.02*10^-6 mole Cl- =4.02*10^-3mmole Cl-

2.97*10^-6 mole Ca^2+ =2.97*10^-3 mmole Ca^2+

5.95*10^-6 mole Cl- = 5.95*10^-3mmole Cl-

Thus there are total Cl- =

0.147 mmol Cl-+4.02*10^-3mmole Cl-+5.95*10^-3mmole Cl-

= 0.15697 mmol Cl-

And

I mol with a valence of 1 = 1 meq / l

1 mol with a valence of 2 = 2 meq / l

Therefore

0.147 mmol Na+
0.147 mmol x its charge of 1 = 0.147 meq/ l

4.02*10^-3 mmole K +

4.02*10^-3 mmol x its charge of 1 = 4.02*10^-3 meq/ l

2.97*10^-3 mmole Ca^2+

2.97*10^-3 mmole Ca^2+ x its charge of 2

  = 5.94*10^-3 meq/ l

0.15697 mmol Cl-

0.15697 x its charge of 1 = 0.15697 meq/ l