In: Statistics and Probability
Consider a sample with a mean of 65 and a variance of 4. What is the minimum percentage of data within the range 60 to 70. Show work
a. .9043
b. .7672
c. .8400
d. .9401
e. None
Solution:
Given:
Mean =
= 65
Variance = s2 = 4
Then standard deviation is square root of variance
thus s = square root of 4
s = 2
We have to find minimum percentage of data within the range 60 to 70.
Use following steps:






and






Thus 60 and 70 are k = 2.5 standard deviations from mean value.
Thus using Chebyshev's theorem, at least
% of data fall within k standard deviations from mean.
Thus find:




Thus correct option is: c. 0.8400