Question

In: Statistics and Probability

A researcher would like to determine if the proportion of households without health insurance coverage differs...

A researcher would like to determine if the proportion of households without health insurance coverage differs with household income. Suppose the following data were collected from

700700

randomly selected households. Complete parts a through c.

Heath Insurance   

Household Income

Yes

No

Less than​ $25,000

55

22

​$25,000 to​ $49,999

145

40

​$50,000 to​ $74,999

201

40

​$75,000 or more

177

20

a. Using alphaαequals=​0.01, perform a​ chi-square test to determine if the proportion of households without health insurance differs by income bracket.

Choose the correct null and alternative hypotheses below.

A.

Upper H 0H0​:

Not all​ p's are equal

Upper H 1H1​:

p 1 equals p 2 equals p 3 equals p 4p1=p2=p3=p4

B.

Upper H 0H0​:

p 1 equals p 2 equals p 3 equals p 4p1=p2=p3=p4

Upper H 1H1​:

p 1 not equals p 2 not equals p 3 not equals p 4p1≠p2≠p3≠p4

C.

Upper H 0H0​:

p 1 not equals p 2 not equals p 3 not equals p 4p1≠p2≠p3≠p4

Upper H 1H1​:

p 1 equals p 2 equals p 3 equals p 4p1=p2=p3=p4

D.

Upper H 0H0​:

p 1 equals p 2 equals p 3 equals p 4p1=p2=p3=p4

Upper H 1H1​:

Not all​ p's are equal

What is the test​ statistic?

chi squaredχ2equals=nothing

​(Round to two decimal places as​ needed.)

What is the critical​ value?

chi Subscript 0.01 Superscript 2χ20.01equals=nothing

​(Round to two decimal places as​ needed.)

State the conclusion.

Do not reject

Reject

Upper H 0H0.

There is

sufficient

insufficient

evidence that the proportion of households without health insurance differs by income bracket.

b. Interpret the meaning of the​ p-value.

What is the​ p-value?

​p-valueequals=nothing

​(Round to three decimal places as​ needed.)

What does the​ p-value mean? Select the correct choice and fill in the answer box to complete your choice.

​(Round to one decimal place as​ needed.)

A.There is a

nothing​%

chance of observing a test statistic value greater than the actual test statistic value if there is no difference in the proportion of households without health insurance.

B.There is a

nothing​%

chance of rejecting the null hypothesis when it should not be rejected.

C.Given a very large number of​ samples, there is a

nothing​%

chance of observing a sample with the given data.

c. How does income appear to impact the likelihood that a household has insurance​ coverage?

A.

The proportion of households without health insurance is always uniform and does not depend on income bracket.

B.The proportion of households without health insurance

does not differdoes not differ

by income bracket.

C.

The proportion of households without health insurance increases as income increases.

D.The proportion of households without health insurance

differs by income bracket.

Click to select your answer(s).

Solutions

Expert Solution

(a) The correct null and alternative hypotheses:

D. H0: p1=p2=p3=p4

H1: Not all​ p's are equal

>> The test​ statistic: χ2 = 16.27

>> The critical​ value: χ2​​​0.01 = 11.34

>> Reject H0. There is sufficient evidence that the proportion of households without health insurance differs by income.

(b) p-value = 0.001

>> A.There is a 1% chance of observing a test statistic value greater than the actual test statistic value if there is no difference in the proportion of households without health insurance.

(c) D. The proportion of households without health insurance differs by income.

** Software Outputs:

Actual Values:
55 22
145 40
201 40
177 20

Expected Values:
63.58 13.42
152.757 32.2429
198.997 42.0029
162.666 34.3343

Chi-Squared Values:
1.15786 5.48557
0.393915 1.86625
0.0201583 0.0955039
1.26315 5.98445

Chi-Square = 16.2669

Degrees of Freedom = 3

p-value = 0.000999707


Related Solutions

A researcher would like to determine if the proportion of households without health insurance coverage differs...
A researcher would like to determine if the proportion of households without health insurance coverage differs with household income. Suppose the following data were collected from 700 randomly selected households. Complete parts a through c. Health Insurance Household Income Yes No Less than $25,000 52 23 $25,000 to $49,999 143 41 $50,000 to $74,999 200 37 $75,000 or more 180 24 a. Using α=0.01, perform a​ chi-square test to determine if the proportion of households without health insurance differs by...
A researcher would like to determine if the proportion of households without health insurance coverage differs...
A researcher would like to determine if the proportion of households without health insurance coverage differs with household income. Suppose the following data were collected from 700 randomly selected households. Complete parts a through c. Household_Income   Yes   No Less_than_25,000 53 20 25,000_to_49,999 143 41 50,000_to_74,999 205 37 75,000_or_more 174 27 a. Using alpha= ​0.01, perform a​ chi-square test to determine if the proportion of households without health insurance differs by income bracket. What is the test statistic? What is the...
A researcher would like to determine if the proportion of households without health insurance coverage differs...
A researcher would like to determine if the proportion of households without health insurance coverage differs with household income. Suppose the following data were collected from 700 randomly selected households. Complete parts a through c. Heath Insurance    Household Income Yes No Less than​ $25,000 50 20 ​$25,000 to​ $49,999 141 44 ​$50,000 to​ $74,999 201 35 ​$75,000 or more 179 30 a. Using alphaαequals=​0.01, perform a​ chi-square test to determine if the proportion of households without health insurance differs...
A car insurance company would like to determine the proportion of accident claims covered by the...
A car insurance company would like to determine the proportion of accident claims covered by the company. According to a preliminary estimate 40% of the claims are covered. How large a sample should be taken to estimate the proportion of accident claims covered by the company if we want to be 90% confident that the sample percentage is within  2% of the actual percentage of the accidents covered by the insurance company?
A car insurance company would like to determine the proportion of accident claims covered by the...
A car insurance company would like to determine the proportion of accident claims covered by the company. According to a preliminary estimate, 60 percent of the claims are covered. How large a sample should be taken to estimate the proportion of accident claims covered by the company if we want to be 98 percent confident that the sample percentage is within ±3 percent of the actual percentage of the accidents covered by the insurance company?
5. A car insurance company would like to determine the proportion of accident claims covered by...
5. A car insurance company would like to determine the proportion of accident claims covered by the company. According to a preliminary estimate 65% of the claims are covered. How large a sample should be taken to estimate the proportion of accident claims covered by the company if we want to be 95% confident that the sample percentage is within 2% of the actual percentage of the accidents covered by the insurance company?
The marketing director for a cereal company would like to know what proportion of households that...
The marketing director for a cereal company would like to know what proportion of households that receive free samples of cereal with their newspapers later purchase the cereal. A random sample showed 55 out of 100 purchased the cereal after receiving the free sample. Find a 95% confidence interval for the true proportion.
1.The marketing department for a cereal company would like to know what "proportion" of households that...
1.The marketing department for a cereal company would like to know what "proportion" of households that receive free samples of the cereal with their newspapers later purchased the cereal. A random sample of 100 showed 55 purchased the cereal.Find a 95% confidence interval for the true proportion.
An insurance company would like to test the hypothesis that a difference exists in the proportion...
An insurance company would like to test the hypothesis that a difference exists in the proportion of students in 12th grade who text while driving when compared to the proportion of 11th grade drivers who text. A random sample of 160 12th grade students found that 84 texted while driving. A random sample of 17511th grade students found that 70 texted while driving. Assume Population 1 is defined as 12th grade drivers and Population 2 is defined as 11th grade...
An insurance company would like to test the hypothesis that a difference exists in the proportion...
An insurance company would like to test the hypothesis that a difference exists in the proportion of students in 12th grade who text while driving when compared to the proportion of 11th-grade drivers who text. A random sample of 160 12th grade students found that 84 texted while driving. A random sample of 175 11th grade students found that 84 texted while driving. A random sample of 175 12th grade drivers and Population 2 is defined as 11th-grade drivers. What...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT