In: Statistics and Probability
x |
0 1 2 3 4 |
P(x) |
.73 .16 .06 .04 .01 |
x |
P(x) |
xP(x) |
x2 |
x2P(X) |
X | P(X) | X*P(X) | X² * P(X) |
0 | 0.7300 | 0.000 | 0.000 |
1 | 0.1600 | 0.160 | 0.160 |
2 | 0.0600 | 0.120 | 0.240 |
3 | 0.0400 | 0.120 | 0.360 |
4 | 0.0100 | 0.040 | 0.160 |
P(X) | X*P(X) | X² * P(X) | |
total sum = | 1 | 0.44 | 0.92 |
mean = E[X] = Σx*P(X) =
0.4400
E [ X² ] = ΣX² * P(X) =
0.9200
variance = E[ X² ] - (E[ X ])² =
0.7264
std dev = √(variance) =
0.8523
................
Sample size , n = 12
Probability of an event of interest, p =
0.2
P ( X = 6) = C (12,6) * 0.2^6 * ( 1 - 0.2)^6=
0.0155
P ( X = 0) = C (12,0) * 0.2^0 * ( 1 - 0.2)^12= 0.0687
p(atleast 6) =0.0039
p(atmost 3) =0.7946
....................
THANKS
revert back for doubt
please upvote