In: Statistics and Probability
The Krasnapolski is a top-of-the-line hotel in Amsterdam, the Netherlands. Among their many services, they rent bicycles to guests. The bicycle checkout is open 24 hours per day 7 days per week and has 50 bicycles on hand. On average, 10 guests request a bicycle each day, arriving completely randomly at all times of the day during the spring and summer seasons. Guests keep bicycles for four days on average, with a standard deviation of two days. Remember: any time you see the term "random" associated with the job arrivals it means the coefficient of variation is equal to one; that is, the standard deviation in the time between arrivals is equal to the mean time between arrivals.
How long does a guest on average have to wait for a bike?
1. Approximately 47 minutes
2. Approximately 4 days
3. Approximately 24 hours
4. Approximately 0.033 hours
Sol:
Let X is random variable.
and X follows normal follows normal distribution with mean 4 days and variance 4 days.
we know that ,
~ N(
standard deviation of =/
Z score is
Z = ( - ) //
we want to find , p(10) = P(Z (10-4)/2/) = P(Z21.213) =1
So guest has to wait for approximately 1 day i.e 24 hours.