Question

In: Statistics and Probability

The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...

The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.

Day 1 2 3 4

Day shift 12 12 16 19

Afternoon shift 10 10 12 15

At the 0.010 significance level, can we conclude there are more defects produced on the day shift? Hint: For the calculations, assume the day shift as the first sample.

a. State the decision rule. (Round your answer to 2 decimal places.)

b. Compute the value of the test statistic. (Round your answer to 3 decimal places.)

c. What is the p-value?

d. What is your decision regarding H0?

Solutions

Expert Solution

If you understood my answer plz rate me positively .

thanks ?

orchestra answered 1 year ago
Next > < Previous

Related Solutions

The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 10 12 13 18 Afternoon shift 9 10 14 15 At the 0.050 significance level, can we conclude there are more defects produced on the day shift? Hint: For the...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 12 12 16 19 Afternoon shift 10 10 12 15 At the 0.010 significance level, can we conclude there are more defects produced on the day shift? Hint: For the...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 10 11 14 18 Afternoon shift 8 11 12 15 At the 0.100 significance level, can we conclude there are more defects produced on the day shift? Hint: For the...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 11 12 13 19 Afternoon shift 9 10 14 15 At the 0.025 significance level, can we conclude there are more defects produced on the day shift? Hint: For the...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 11 10 14 17 Afternoon shift 8 11 12 15 At the 0.010 significance level, can we conclude there are more defects produced on the day shift? Hint: For the...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 11 11 16 19 Afternoon shift 10 9 14 16 At the 0.010 significance level, can we conclude there are more defects produced on the day shift? Hint: For the...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 12 12 16 19 Afternoon shift 12 10 16 18 At the 0.100 significance level, can we conclude there are more defects produced on the day shift? Hint: For the...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 10 11 14 18 Afternoon shift 8 11 12 15 At the 0.100 significance level, can we conclude there are more defects produced on the day shift? Hint: For the...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 10 10 16 17 Afternoon shift 9 10 14 15 At the 0.100 significance level, can we conclude there are more defects produced on the day shift? Hint: For the...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 11 12 14 18 Afternoon shift 8 9 13 16 At the 0.025 significance level, can we conclude there are more defects produced on the day shift? Hint: For the...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT