In: Advanced Math
2. Let D be a relation on the natural numbers N defined by D = {(m,n) : m | n} (i.e., D(m,n) is true when n is divisible by m. For this problem, you’ll be proving that D is a partial order. This means that you’ll need to prove that it is reflexive, anti-symmetric, and transitive.
(a) Prove that D is reflexive. (Yes, you already did this problem on one of the minihomework assignments. You don’t have to redo the problem, but you should at least copy over your answer from that assignments to this one.)
(b) Prove that D is anti-symmetric. You may use the following fact: for any two natural numbers m and n, if m·n = 1, then m = 1 and n = 1. (Note that D is only anti-symmetric because the domain is the natural numbers. If we switched to the domain of integers, then things would be completely different.)
(c) Prove that D is transitive. (You’ve probably done a problem already that is almost exactly the same as this.)