Question

PYTHON PLS

1) Create a function search_by_pos. This function only has one return statement. This function returns a set statement that finds out the same position and same or higher skill number. This function searches the dictionary and returns the same position and same or higher skill level. The function output the set statements that include the position only.

For example

input : dict = {'Fiora': {'Top': 1, 'Mid': 4, 'Bottom': 3},'Olaf': {'Top': 3, 'Mid': 2, 'Support': 4},'Yasuo': {'Mid': 2, 'Top': 5},'Shaco': {'Jungle': 4, 'Top': 2, 'Mid': 1}}

def search_by_pos(dict, 4):

#ONLY ONE RETURN STATEMENT ALLOWED

output : {'Mid', 'Support','Top','Jungle'}

2) Create a function search_by_rank this function calculates the average skill level for each champion and returns the champion's name by highest to the lowest average skill level. If two champions have the same average skill level, it must appear in increasing alphabetical order by name. This function needs to have only one return statement.

For example

input : dict = {'Fiora': {'Top': 1, 'Mid': 4, 'Bottom': 3},'Olaf': {'Top': 3, 'Mid': 2, 'Support': 4},'Yasuo': {'Mid': 2, 'Top': 5},'Shaco': {'Jungle': 4, 'Top': 2, 'Mid': 1}}

def search_by_rank(dict):

#ONLY ONE RETURN STATEMENT ALLOWED

output: ['Yasuo', 'Olaf', 'Fiora', 'Shaco']

Answer 1

Code:-

d1 = {'Fiora': {'Top': 1, 'Mid': 4, 'Bottom': 3},'Olaf': {'Top': 3, 'Mid': 2, 'Support': 4},'Yasuo': {'Mid': 2, 'Top': 5},'Shaco': {'Jungle': 4, 'Top': 2, 'Mid': 1}}

def search_by_pos(di,n): # define function
    result=[]# to store the result
    for i in di.keys():# iterate over an every item of main dict
        for j in di[i].keys(): # iterate items inside every item of main dict
            if di[i][j]>=n:# check if equal or more then required value
                result.append(j)# if yes the add it into to result
    return result# return result
search_by_pos(d1,n) # calling function

from operator import itemgetter # this will used for sorting dict or list over multiple field
def search_by_rank(di): #main function
    result=[] # for store sorted list from dict
    for i in di.keys(): # loop over every item in main dict
        sum1=0# for sum up skills of every item in main dict
        for j in di[i].keys():# iterate over dict inside dict means dict for every item in main dict
            sum1+=di[i][j] # sumup thier skill
        result.append([i,sum1/len(di[i].keys())]) # now add this into result
    #this line will return name in sorted manner as per your requirment
    return [i[0] for i in sorted(result,key=itemgetter(1,0),reverse=True)]
          
search_by_rank(di)    
   

Output:---

Note :- sorted(result,key=itemgetter(1,0),reverse=True this will iterate items in result list and return the avrage skills and then name so it will help us to sort value as we need.