This figure shows the interaction of a cation with surrounding water molecules.

Would you expect the energy of ion–solvent interaction to be greater for Na+ or Li+? Explain.

Expert Solution

Ion-solvent interactions inversely proportion al to the size of the ion. I.e. smaller is the ion greater is the force of attraction between solvent molecules and ion. Hence more solvent molecules are surrounded by the ion.

The radius of Na+ > Li+.

The energy released when one mole of particular ions are sur rounded by water molecules is called hydration enthalpy ΔHhyd.

The value of ΔHhyd for Li+ is more than that of Na+ ion.

Ion-solvent interactions inversely proportion al to the size of the ion. I.e. smaller is the ion greater is the force of attraction between solvent molecules and ion. Hence more solvent molecules are surrounded by the ion.

Junaid answered 2 years ago

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