In: Statistics and Probability
EXPERIMENT 1
Part 1:
Dr. Saunders wanted to know whether adolescents who had restricted television viewing time studied more than adolescents who had unlimited television viewing time. She recruited a small sample of children aged 12 to 17 years old; some of these children were allowed limited access to their home televisions, and others were allowed unlimited access. She obtained the following studying time data (in minutes) fore the two groups:
Limited |
Unlimited |
91 |
29 |
68 |
34 |
73 |
65 |
94 |
28 |
75 |
21 |
88 |
57 |
Enter these data into SPSS in the appropriate manner for the type of analysis you will conduct. Label the columns appropriately.
After you answer questions about the appearance of the information in Data View, you will conduct the appropriate statistical test.
Question 1 options:
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2. What text goes in the header of the first column?
3. Enter all the numbers or words you see in the second column in SPSS data view in the same order they are shown in that column.
Question 3 options:
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4. What text goes in the header of the second column?
Part 2:
Using SPSS compute the appropriate statistical test to determine whether there is a difference in study time between the children with limited vs. unlimited television viewing. Fill in the empty cells based on the output of the statistical test you conducted.
Write your answer to the same number of decimal places as you see in your SPSS output.
|
SPSS data
Group Statistics |
|||||
Group |
N |
Mean |
Std. Deviation |
Std. Error Mean |
|
time |
Limited |
6 |
81.5000 |
10.82128 |
4.41777 |
Unlimited |
6 |
39.0000 |
17.72005 |
7.23418 |
Independent Samples Test |
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Levene's Test for Equality of Variances |
t-test for Equality of Means |
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F |
Sig. |
t |
df |
Sig. (2-tailed) |
Mean Difference |
Std. Error Difference |
95% Confidence Interval of the Difference |
|||
Lower |
Upper |
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time |
Equal variances assumed |
2.477 |
0.147 |
5.014 |
10 |
0.001 |
42.50000 |
8.47644 |
23.61332 |
61.38668 |
Equal variances not assumed |
5.014 |
8.274 |
0.001 |
42.50000 |
8.47644 |
23.06539 |
61.93461 |
Part 3:
k is the t value 5.014
l is the d.f. 10
m is the Sig (2-tailed) 0.001
n is the mean difference 42.5
10
.001
Children with limited television viewing do have significantly study more time than who unlimited time viewing television , t(10)=5.014, p=0.001.
Group |
M |
Difference Between the Means |
Standard Deviation |
p |
Limited |
81.50 |
42.50 |
10.82 |
0.001 |
Unlimited |
39.00 |
17.72 |
Yes