Question

In: Statistics and Probability

A new operator was recently assigned to a crew of workers who perform a certain job....

A new operator was recently assigned to a crew of workers who perform a certain job. From the records of the number of units of work completed by each worker each day last month, a sample of size five was randomly selected for each of the two experienced workers and the new worker. At the α = .05 level of significance, does the evidence provide sufficient reason to reject the claim that there is no difference in the amount of work done by the three workers?

Workers
New A B
Units of work (replicates) 9 11 13
8 10 11
10 13 9
8 13 11
10 13 12

(a) Find the test statistic. (Give your answer correct to two decimal places.)


(ii) Find the p-value. (Give your answer bounds exactly.)
_____< p < ____

An experiment was designed to compare the lengths of time that four different drugs provided pain relief after surgery. The results (in hours) follow. Is there enough evidence to reject the null hypothesis that there is no significant difference in the length of pain relief provided by the four drugs at α = .05?

Drug
A B C D
4 5 7 2
5 5 8 2
3 6 12 4
4 5 9
10

(a) Find the test statistic. (Give your answer correct to two decimal places.)


(ii) Find the p-value. (Give your answer bounds exactly.)
____< p < ____

Solutions

Expert Solution

Ans a ) using excel>data>data analysis >one way ANOVA

we have

Anova: Single Factor
SUMMARY
Groups Count Sum Average Variance
New 5 45 9 1
A 5 60 12 2
B 5 56 11.2 2.2
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 24.13333 2 12.06667 6.961538 0.009839 3.885294
Within Groups 20.8 12 1.733333
Total 44.93333 14

(a) the test statistic F = 6.96

(ii)the p-value
0.005<p <0.01

Ans 2 )

using excel>data>data analysis >one way ANOVA

we have

Anova: Single Factor
SUMMARY
Groups Count Sum Average Variance
A 4 16 4 0.666667
B 4 21 5.25 0.25
C 5 46 9.2 3.7
D 3 8 2.666667 1.333333
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 101.2208 3 33.74028 20.02721 5.78E-05 3.490295
Within Groups 20.21667 12 1.684722
Total 121.4375 15

(a) the test statistic F = 20.03

(ii)the p-value
0.<p <0.00001


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