Question

Calcium carbonate heated up to 700 oC decomposes to calcium oxide and carbon dioxide. CaCO3 -- CaO + CO2 a. How many moles of carbon dioxide can be generated from 300g of calcium carbonate. b. How many grams of carbon dioxide can be generated from 300g of calcium carbonate.

Answer 1

ANSWER:

The given reaction is:

CaCO₃ CaO + CO₂

(a) Given,

mass of calcium carbonate = 300g

molecular mass of calcium carbonate = 100.0869 g/mol

number of moles of calcium carbonate = (given mass)/(molecular mass)

= (300 g)/(100.0869 g/mol)

= 2.9974 mol

From reaction,

1 mole of calcium carbonate generates = 1 mole of carbon dioxide

2.9974 mol of calcium carbonate generates = 2.9974 mole of carbon dioxide

Hence, 2.9974 moles of carbon dioxide can be generated from 300g of calcium carbonate.

(b) Given,

Number of moles of carbon dioxide = 2.9974 moles

molecular mass of carbon dioxide = 44.01 g/mol

mass of carbon dioxide = Number of moles x molecular mass

= 2.9974 mol x 44.01 g/mol

= 131.92 g

Hence, 131.92 grams of carbon dioxide can be generated from 300g of calcium carbonate.