Question

Using MATLAB:

The velocity, v, and the distance, d, as a function of time, of a car that accelerates from rest at constant acceleration, a, are given by

= a n d = 12

Determine v and d at every second for the first 10 seconds for a car with acceleration of = 15 ft/s2. Your output must have exactly the same format as the template table below. Note that dots have been added to the table below; you can count the dots to determine the exact spacings. Also note the units.

··········Time (s) ······· ···Distance (ft) ·········Velocity (mph) ··········x.x·················x.xxe+yy···············x.xxx

Answer 1

MATLAB CODE

clear
clc;
a = 15; %ft/s2 (acceleration)
for i = 1:10
    t(i) = i; %time span
    d(i) = 12 + (1/2)*a*t(i)^2; % initial distane is 12 ft.
    v(i) = a*t(i)*(3600/5280); % 1 mile = 5280 ft and 1h =3600 sec
end
table = [t' d' v']

Ans

Time(s)	Distance(ft)	velocity (mph)
1.0000	19.5000	10.2273
2.0000	42.0000	20.4545
3.0000	79.5000	30.6818
4.0000	132.0000	40.9091
5.0000	199.5000	51.1364
6.0000	282.0000	61.3636
7.0000	379.5000	71.5909
8.0000	492.0000	81.8182
9.0000	619.5000	92.0455
10.0000	762.0000	102.2727