In: Chemistry
Question:
For each solution 1-7 calculate the following information. Show all
your calculations below.
-Then it gives you a blank chart with --- column 1: Test tube 1-7;
column 2: [Fe3+]; column 3: [SCN-]; column 4:
mole fraction SCN-
This is the rest of the information given-
Test tube 1: Volume of Fe3+ solution added: 0mL;
Volume of SCN- solution added: 10mL
Test tube 2: Volume of Fe3+ soln added: 2mL;
Volume of SCN- soln added: 8mL
Test tube 3: Volume of Fe3+ soln added: 4mL;
Volume of SCN- soln added: 6mL
Test tube 4: Volume of Fe3+ soln added: 5mL;
Volume of SCN- soln added: 5mL
Test tube 5: Volume of Fe3+ soln added: 6mL;
Volume of SCN- soln added: 4mL
Test tube 6: Volume of Fe3+ soln added: 8mL;
Volume of SCN- soln added: 2mL
Test tube 7: Volume of Fe3+ soln added: 10mL;
Volume of SCN- soln added: 0mL
50 mL of 0.0020 M solution of KSCN in .5 M HNO3
0.0020 M Fe(NO3)3 solution in .50 M HNO3
for the given solution,
[Fe3+] = molarity of stock solution x volume of stock solution/total volume
[SCN-] = molarity of stock solution x volume of stock solution/total volume
So,
test tube [Fe3+] (M) [SCN-] (M) mole fraction [SCN-]
1 0 0.002 1
2 0.0004 0.0016 0.8
3 0.0008 0.0012 0.6
4 0.0001 0.001 0.5
5 0.0012 0.0008 0.4
6 0.0016 0.0004 0.2
7 0.0004 0 0