Question: For each solution 1-7 calculate the following information. Show all your calculations below. -Then it...

Question:
For each solution 1-7 calculate the following information. Show all your calculations below.
-Then it gives you a blank chart with --- column 1: Test tube 1-7; column 2: [Fe³⁺]; column 3: [SCN^-]; column 4: mole fraction SCN^-

This is the rest of the information given-
Test tube 1: Volume of Fe3+ solution added: 0mL; Volume of SCN- solution added: 10mL
Test tube 2: Volume of Fe3+ soln added: 2mL; Volume of SCN- soln added: 8mL
Test tube 3: Volume of Fe3+ soln added: 4mL; Volume of SCN- soln added: 6mL
Test tube 4: Volume of Fe3+ soln added: 5mL; Volume of SCN- soln added: 5mL
Test tube 5: Volume of Fe3+ soln added: 6mL; Volume of SCN- soln added: 4mL
Test tube 6: Volume of Fe3+ soln added: 8mL; Volume of SCN- soln added: 2mL
Test tube 7: Volume of Fe3+ soln added: 10mL; Volume of SCN- soln added: 0mL

50 mL of 0.0020 M solution of KSCN in .5 M HNO₃

0.0020 M Fe(NO₃)₃ solution in .50 M HNO₃

Expert Solution

for the given solution,

[Fe3+] = molarity of stock solution x volume of stock solution/total volume

[SCN-] = molarity of stock solution x volume of stock solution/total volume

So,

test tube [Fe3+] (M) [SCN-] (M) mole fraction [SCN-]

1 0 0.002 1

2 0.0004 0.0016 0.8

3 0.0008 0.0012 0.6

4 0.0001 0.001 0.5

5 0.0012 0.0008 0.4

6 0.0016 0.0004 0.2

7 0.0004 0 0

queen_honey_blossom answered 1 year ago

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