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In: Chemistry

Question: For each solution 1-7 calculate the following information. Show all your calculations below. -Then it...

Question:
For each solution 1-7 calculate the following information. Show all your calculations below.
-Then it gives you a blank chart with --- column 1: Test tube 1-7; column 2: [Fe3+]; column 3: [SCN-]; column 4: mole fraction SCN-

This is the rest of the information given-
Test tube 1: Volume of Fe3+ solution added: 0mL; Volume of SCN- solution added: 10mL
Test tube 2: Volume of Fe3+ soln added: 2mL; Volume of SCN- soln added: 8mL
Test tube 3: Volume of Fe3+ soln added: 4mL; Volume of SCN- soln added: 6mL
Test tube 4: Volume of Fe3+ soln added: 5mL; Volume of SCN- soln added: 5mL
Test tube 5: Volume of Fe3+ soln added: 6mL; Volume of SCN- soln added: 4mL
Test tube 6: Volume of Fe3+ soln added: 8mL; Volume of SCN- soln added: 2mL
Test tube 7: Volume of Fe3+ soln added: 10mL; Volume of SCN- soln added: 0mL

50 mL of 0.0020 M solution of KSCN in .5 M HNO3

0.0020 M Fe(NO3)3 solution in .50 M HNO3

Solutions

Expert Solution

for the given solution,

[Fe3+] = molarity of stock solution x volume of stock solution/total volume

[SCN-] = molarity of stock solution x volume of stock solution/total volume

So,

test tube      [Fe3+] (M)          [SCN-] (M)           mole fraction [SCN-]

     1                    0                      0.002                           1

     2               0.0004                 0.0016                         0.8

     3               0.0008                 0.0012                         0.6

     4               0.0001                 0.001                           0.5

     5               0.0012                 0.0008                         0.4

     6               0.0016                 0.0004                         0.2

     7               0.0004                     0                                0


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