In: Anatomy and Physiology
Side #1 Side #2
Square 1 = 30 white cells Square 1 = 27 white cells
Square 2 = 28 white cells Square 2 = 27 white cells
Square 3 = 25 white cells Square 3 = 24 white cells
Square 4 = 27 white cells Square 4 = 24 white cells
We have, side of one primary square = 1 mm
Therefore, side of one secondary square = 1/4 mm
Now, area of one secondary square = (14) (14) = 1/16 mm2
We have, depth of one secondary square = 1/10 mm
Therefore, volume of one secondary square = (116) (110) = 1/160 mm3
We have 16 secondary squares in each primary square (i.e, square 1, square 2 etc.)
So, total number of secondary squares = (16 4) = 64
Hence, total volume of secondary squares = 64 X (1/160) = 2/5 mm3
Let 'N' be the number of WBCs in 2/5 mm3 of dilated blood.
Then, number of WBCs in 1mm3 of diluted blood = (52) X N
Given, dilution factor = 1/100
Hence, number of WBCs in 1 mm3 of undiluted blood = (5/2) X N X 100 = 250 N (where N = N1 + N2 +N3 + N4)
Slide #1
N = 30 +28 + 25 + 27 = 110
Hence, total number of WBCs in 1mm3 of undiluted blood = 250 X 110 = 27,500
Slide #2
N = 27 + 27+ 24 + 24 = 102
Hence, total number of WBCs in 1mm3 of undiluted blood = 250 X 102 = 25,500