In: Statistics and Probability
You may need to use the appropriate technology to answer this question.
The following data are from a completely randomized design.
Treatment | |||
---|---|---|---|
A | B | C | |
161 | 143 | 126 | |
143 | 157 | 121 | |
164 | 125 | 137 | |
144 | 141 | 139 | |
149 | 137 | 151 | |
169 | 143 | 124 | |
Sample mean |
155 | 141 | 133 |
Sample variance |
122.8 | 107.2 | 130.0 |
(a)
Compute the sum of squares between treatments.
(b)
Compute the mean square between treatments.
(c)
Compute the sum of squares due to error.
(d)
Compute the mean square due to error. (Round your answer to two decimal places.)
(e)
Set up the ANOVA table for this problem. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)
Source of Variation |
Sum of Squares |
Degrees of Freedom |
Mean Square |
F | p-value |
---|---|---|---|---|---|
Treatments | |||||
Error | |||||
Total |
(f)
At the α = 0.05 level of significance, test whether the means for the three treatments are equal.
State the null and alternative hypotheses.
H0: μA =
μB = μC
Ha: μA ≠
μB ≠
μCH0: Not all the
population means are equal.
Ha: μA =
μB =
μC H0:
μA = μB =
μC
Ha: Not all the population means are
equal.H0: At least two of the population means
are equal.
Ha: At least two of the population means are
different.H0: μA ≠
μB ≠ μC
Ha: μA =
μB = μC
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value =
State your conclusion.
Do not reject H0. There is sufficient evidence to conclude that the means for the three treatments are not equal.Reject H0. There is sufficient evidence to conclude that the means for the three treatments are not equal. Do not reject H0. There is not sufficient evidence to conclude that the means for the three treatments are not equal.Reject H0. There is not sufficient evidence to conclude that the means for the three treatments are not equal.