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A container was found in the home of the victim that contained 120 g of ethylene...

A container was found in the home of the victim that contained 120 g of ethylene glycol in 550 g of liquid. How many drinks, each containing 100 g of this liquid, would a 80 kg victim need to consume to reach a toxic level of ethylene glycol?

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Expert Solution

Lethal dose of ethylene glycol for human is 1400mg/kg. Thus to have toxic effects on the victim of 80 kg,

Victim must have consume minimum of = 80×1400mg of ethylene glycol =112000 mg of ethylene glycol.

112000 mg = 112 g of ethylene glycol.

Concentration of ethylene glycol in the liquid is = 120 g/550g =0.2181 g of ethylene glycol per g of liquid.

A drink is made of 100 g of liquid, hence concentration of ethylene glycol in each drink is= 0.2181 × 100 = 218.1 g of ethylene glycol in each drink. Thus theoretically, 0.51 drink are needed to have toxic effects of ethylene glycol to be consumed by victim.

Thus little above half of a drink must have been consumed by the victim.

Please note that toxicity level I have referred is from following link:

https://goo.gl/VnxM7K

queen_honey_blossom answered 2 years ago
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