Question

In: Chemistry

1. How would doubling the concentration of NaOH used for the titration affect the calculated rate...

1. How would doubling the concentration of NaOH used for the titration affect the calculated rate constant? 2. What makes the "blank" titrimetric determination different from the reaction you will be preforming?

Solutions

Expert Solution

1. The rate constant is independent of the concentration of the reactants and products. It is however dependent on the nature of the chemical substance, temperature and the presence of catalyst.

So if we alter the concentration of NaOH, there won't be any effect on rate constant.

Moreover, rate constant is a proportionality between the rate of the reaction and the concentrations raised to the power of it's orders.

2. In blank titrimetry there is no analyte taken. Or the species which is to be determined is absent. It is just taken to correct the error if any. In the reaction medium there may be interfering ions due to which our titration volume may change. So a blank helps us remove those errors.

Hope this helped! Have a good day!


Related Solutions

1. Based on your experimental determined rate law for the reaction of crystal violet and hydroxide ion, how would doubling the concentration of crystal violet affect the reaction rate?
Trial 1 Time Trans A=2-log %T Ln(A) 1/A 1:57 19.0 0.721 -0.327 1.39 2:52 22.0 0.658 -0.419 1.52 3:51 24.5 0.611 -0.493 1.64 4:54 27.3 0.564 -0.573 1.77 5:53 29.7 0.527 -0.641 1.90 6:54 33.6 0.474 -0.747 2.11 7:55 36.2 0.441 -0.819 2.27 8:54 40.0 0.398 -0.921 2.51 9:52 40.5 0.393 -0.934 2.54 10:53 45.3 0.344 -1.07 2.91 11:58 47.7 0.321 -1.14 3.12 13:02 52.2 0.280 -1.27 3.57 14:02 55.3 0.257 -1.36 3.89 14:59 56.0 0.252 -1.38 3.97 15:59 59.4...
Using your calculated concentration of NaOH from lab how many grams of KHP would you need...
Using your calculated concentration of NaOH from lab how many grams of KHP would you need to start with in order to have an end point at 35.00 mL? Do I use 71.08 or 204.22 for KHP Molecular Mass? Concentration of NaOH from the Experiment was .356.
nitial data Enter the concentration of NaOH used in the titration. (M) 0.5 Enter the mass...
nitial data Enter the concentration of NaOH used in the titration. (M) 0.5 Enter the mass of unknown acid you used in grams. (g) 0.75 pH vs Volume Measurements Table 1. pH readings Volume (mL) pH Initial measurement 0 1.43 Data point 1 0.99 1.23 Data point 2 2 1.41 Data point 3 2.97 1.5 Data point 4 3.99 1.59 Data point 5 4.99 1.69 Data point 6 5.99 1.79 Data point 7 6.98 1.89 Data point 8 7.99 2...
Exercise 1: Determining the Concentration of Acetic Acid Data Table 1. NaOH Titration Volume Initial NaOH...
Exercise 1: Determining the Concentration of Acetic Acid Data Table 1. NaOH Titration Volume Initial NaOH Volume (mL) Final NaOH Volume (mL) Total volume of NaOH used (mL) Trial 1 7ml 0 7 Trial 2 7ml 0.4 6.7 Trial 3 7ml 0.6 6.5 Data Table 2. Concentration of CH3COOH in Vinegar Average volume of NaOH used (mL) Concentration CH3COOH in vinegar (mol/L) % CH3COOH in vinegar 6.7 65mol/L 77% Questions: If the manufacturer of the vinegar used in the experiment...
In the titration of H3PO4 with 0.1122 M NaOH, 33.25 mL of titrant is used. How...
In the titration of H3PO4 with 0.1122 M NaOH, 33.25 mL of titrant is used. How many moles of phosphoric acid were in the original sample?
1. For each of the following circumstances, indicate wheter the calculated molarity of NaoH would be...
1. For each of the following circumstances, indicate wheter the calculated molarity of NaoH would be lower, higher, or unaffected. Explain your answer in each case. a. The inside of the pipet used to transfer the standard HCl solution was wet with water. b. You added 40 mL of water to the titration flask rather than 25 mL. c. The buret, wet with water, was not rinsed with NaOH solution before filling the buret with NaOH with solution. d. Five...
Show how you would find the concentration of a diprotic acid that was titrated with NaOH?...
Show how you would find the concentration of a diprotic acid that was titrated with NaOH? Find the concentration of a diprotic acid when 24.55mL of the acid requires 32.57 mL of 0.1059 M NaOH.
A titration experiment is done with 1.37E-2 M NaOH to determine the acid concentration in 0.631...
A titration experiment is done with 1.37E-2 M NaOH to determine the acid concentration in 0.631 L of an unknown acidic solution. It was found that to reach the equivalence point 12.3 mL of strong base was needed. What was the pH of the original acidic solution?
1) Determine how the following error would affect calculated the percent yield of alum. (increase, decrease,...
1) Determine how the following error would affect calculated the percent yield of alum. (increase, decrease, no effect). Briefly explain. 1a. The Aluminum foil did not completely react. 1b. Alum sample was left in the beaker and not transferred to the filter paper. 1c. Alum Sample was not dried completely in the oven. 2) A piece of an aluminum can was cut into small pieces. Then 0.422g of the pieces from the can was used to prepare potassium alum according...
1) Indicate how each of the following errors would affect(increase, decrease, or no change) your calculated...
1) Indicate how each of the following errors would affect(increase, decrease, or no change) your calculated value for the molar volume of O2 at STP (assuming that you complete the experiment otherwise correctly). In each case, explain your answer. a. you forgot to subtract the vapor pressure of water in determining the pressure of O2 b. while heating your sample in the test tube your flame was improperly adjusted so that the black soot formed on the outside of the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT