Question

In: Statistics and Probability

Question 1: Given the following probability distribution for a random variable X: x P(X=x) -2 0.30...

Question 1:
Given the following probability distribution for a random variable X: x P(X=x)
-2
0.30
-1
0.15
0
0.20
1
0.20
2
0.15
a) Explain two reasons why the above distribution is a valid probability distribution.
b) Calculate μX and σX.
c) Determine the cdf(X), and write it as an additional column in the table.
d) Calculate P(−1<X≤3) .
e) Draw a histogram that represents the probability distribution of X.

Solutions

Expert Solution

Question 1 :

The probability distribution of X is

x -2 -1 0 1 2 Total
P(X=x) 0.30 0.15 0.20 0.15 0.15 1

a) i) Since for every value of X

ii) Total of all probabilities is 1.

Hence given probability distribution is valid.

b)

x p x*p x2*p
-2 0.3 -0.6 1.2
-1 0.15 -0.15 0.15
0 0.2 0 0
1 0.2 0.2 0.2
2 0.15 0.3 0.6
Total 1 -0.25 2.15

The expected value of X is given by

Variance of X is given by

Standard deviation of X is

c) Cumulative distribution function of X is

x p F(x)
-2 0.3 0.3
-1 0.15 0.45
0 0.2 0.65
1 0.2 0.85
2 0.15 1

d)

= 0.2 + 0.2 +0.15

= 0.55

e) For drawing histogram

Consider total frequency = 100

By using R

> x=seq(-2,2,1)
> y=c(30,15,20,20,15)
> f=rep(x,y)
> hist(f)
> t=seq(-2.5,2.5,1)
> hist(f,breaks=t,main="Histogram")


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