In: Statistics and Probability
I would like to know how to solve this problem using POM or Excel
Alan Resnik, a friend of Ray Cahnman, bet Ray $5 that Ray’s car would not start 5 days from now (see Problem 14-8).
What is the probability that it will not start 5 days from now if it started today?
What is the probability that it will not start 5 days from now if it did not start today?
What is the probability that it will start in the long run if the matrix of transition probabilities does not change?
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Answer:
(a)
If: p(0) = (1 0), p(1) = (0.9, 0.1), p(5) = (0.76944, 0.23056)
Probability that it will not start in five days from today is 23.056%.
(b)
If: p(0) = (0 1), p(1) = (0.3, 0.7), p(5) = (0.69168, 0.30832)
Probability that it will not start five days from today is 30.832%
(c)
Markov Analysis Results above: In equilibrium p = pP
p1 = 0.9p1 + 0.3p2 p2 = 0.1p1 + 0.7p2 p1 + p2 = 1 or, p1 = 0.75, p2 = 0.25
Therefore, long-run probability of starting is 75%.