Question

An object is 1.6 m to the left of a lens of focal length 0.6 m. A second lens of focal length -4 m is 0.58 m to the right of the first lens. Find the distance between the object and the final image formed by the second lens.

____ m

What is the overall magnification (with sign)?

Is the final image real or virtual?

Is it upright or inverted?

Answer 1

Here is what I solved before, please modify the figures as per your question. Please let me know if you have further questions. Ifthis helps then kindly rate 5-stars.

An object is 1.85 m to the left of a lens of focal length 0.6 m. A second lens of focal length -2.7 m is 0.4 m to the right of the first lens. Find the distance between the object and the final image formed by the second lens. What is the overall magnification (with sign)?

answer

Start with the first lens

1/f = 1/q + 1/p

1/.6 = 1/1.85 + 1/q

q = .888 m behind the first lens

Since the lenses are .4 m apart this image is .488 m behind the lens, so the object distance is -.488

1/-2.7 = 1/-.488 + 1/q

q = .596 m

Meaning that the final image is .596 m behind the second lens

So, total distance between object and final image is

1.85 + .4 + .596 = 2.846m

The magnification of the first lens is M = -q/p = -.888/1.85 = -.48

The magnification of the second lens is M = -q/p = -(.596)/-.488 = 1.22

Total magnification is (-.48)(1.22) = -.586