Question

In: Statistics and Probability

In the following exercises, assuming that the thermometer readings are normally distributed, with a mean of...

In the following exercises, assuming that the thermometer readings are normally distributed, with a mean of 0 celsius and a standard deviation of 1.00 celsius. A thermometer is randomly selected and tested. In each case, calculate the probability of each reading.

a) P(z>1.645)

Solutions

Expert Solution

Answer: P(z>1.645) = 0.05

>> From z distribution table,

P(z<1.64) = 0.9495

P(z<1.65) = 0.9505

By averaging those two, we get

P(z<1.645) = (0.9495+9505)/2 = 0.95

Thus, P(z>1.645) = 1 - P(z<1.645) = 1 - 0.95 = 0.05


Related Solutions

Systolic blood pressure readings for females are normally distributed with a mean of 125 and a...
Systolic blood pressure readings for females are normally distributed with a mean of 125 and a standard deviation of 10.34. If 60 females are randomly selected then find the probability that their mean systolic blood pressure is between 122 and 126. Give your answer to four decimal places.
Assume that blood pressure readings are normally distributed with a mean of 124 and a standard...
Assume that blood pressure readings are normally distributed with a mean of 124 and a standard deviation of 9.6. If 144 people are randomly​ selected, find the probability that their mean blood pressure will be less than 126. Round to four decimal places.
Assume that blood pressure readings are normally distributed with a mean of 115 and a standard...
Assume that blood pressure readings are normally distributed with a mean of 115 and a standard deviation of 4.8. if 33 people are randomly selected, find the probability that their mean blood pressure will be less than 117.
Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard...
Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the probability that a randomly selected thermometer reads between -2.05 and −1.18
Blood pressure readings are normally distributed with a mean of 120 and a standard deviation of...
Blood pressure readings are normally distributed with a mean of 120 and a standard deviation of 8. a. If one person is randomly selected, find the probability that their blood pressure will be greater than 125. b. If 16 people are randomly selected, find the probability that their mean blood pressure will be greater than 125. 5 c. Why can the central limit theorem be used in part (b.), even that the sample size does not exceed 30?
Assume that blood pressure readings are normally distributed with a mean of 123 and a population...
Assume that blood pressure readings are normally distributed with a mean of 123 and a population standard deviation of 9.6. If 67 people are randomly selected, find the probability that their mean blood pressure will be less than 125.
Assuming IQ scores are normally distributed in the population with a mean of 100 and a...
Assuming IQ scores are normally distributed in the population with a mean of 100 and a standard deviation of 16, what percentages of IQ scores are less than 120, between 110 and 130, and what IQ will place you in the top 8% of the population?
2. . Determine the value for x assuming that X is normally distributed with a mean...
2. . Determine the value for x assuming that X is normally distributed with a mean of 15 and a standard deviation of 2. (a) P(X < 11) (b) P(X > 0) (c) P(3 < X < 7) (d) P(-2 < X < 9) (e) P(2 < X < 8)
Assuming that the population is normally​ distributed, construct a 99% confidence interval for the population​ mean,...
Assuming that the population is normally​ distributed, construct a 99% confidence interval for the population​ mean, based on the following sample size of n=7.​ 1, 2,​ 3,4, 5, 6​,and 30   Change the number 30 to 7 and recalculate the confidence interval. Using these​ results, describe the effect of an outlier​ (that is, an extreme​ value) on the confidence interval. Find a 99 % confidence interval for the population mean. ​(Round to two decimal places as​ needed.) Change the number 30...
Assuming that the population is normally​ distributed, construct a 9090​% confidence interval for the population mean...
Assuming that the population is normally​ distributed, construct a 9090​% confidence interval for the population mean for each of the samples below. Explain why these two samples produce different confidence intervals even though they have the same mean and range. Sample​ A: 11    22    33    33    66    66    77    88 Full data set Sample​ B: 11    22    33    44    55    66    77    88 Construct a 9090​% confidence interval for the population mean for sample A. nothing less than or equals≤muμless...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT