For which of the following reactions will the entropy of the system decrease? 2 C(s) +...

For which of the following reactions will the entropy of the system decrease?

		2 C(s) + O₂(g) → 2 CO(g)
		CaO(s) + CO₂(g) → CaCO₃(s)
		N₂O₄(g) → 2 NO₂(g)
		KOH(s) → K⁺(aq) + OH^–(aq)
		2 NH₃(g) → N₂(g) + 3 H₂(g)

Solutions

Expert Solution

B is right answer. Here is explanation

Entropy is measure of disorder of the system. Gaseous substance has most entropy and solid substance has least entropy. In gaseous substance molecules are free to move so more disorder. While in the solid, particles are fixed so negligible disorder.

gas >> liquid >>> solid

C_(s) < O_2(g)

entropy

Entropy also depend on amount of substance.

1 mole O₂ > 2 mole O₂ > 3 mole O₂

(A) Reactant has solid carbon and one mole O₂

Product has 2 mole of CO. So product has more entropy

(B) Reactant has gaseous substance while product has only solid substance. So in this case entropy of system will decrease.

(D) Reactant is solid while product ions in aqueous phase so product has more entropy.

(E) 2 moles of reactant gas gives total 4 mole of product gas. so product has more entropy than reactant

queen_honey_blossom answered 1 year ago

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