Question

In: Chemistry

For which of the following reactions will the entropy of the system decrease? 2 C(s) +...

For which of the following reactions will the entropy of the system decrease?

2 C(s) + O2(g) → 2 CO(g)

CaO(s) + CO2(g) → CaCO3(s)

N2O4(g) → 2 NO2(g)

KOH(s) → K+(aq) + OH–(aq)

2 NH3(g) → N2(g) + 3 H2(g)

Solutions

Expert Solution

B is right answer. Here is explanation

Entropy is measure of disorder of the system. Gaseous substance has most entropy and solid substance has least entropy. In gaseous substance molecules are free to move so more disorder. While in the solid, particles are fixed so negligible disorder.

gas >> liquid >>> solid

C(s) < O2(g)

entropy

Entropy also depend on amount of substance.

1 mole O2 > 2 mole O2 > 3 mole O2

(A) Reactant has solid carbon and one mole O2

Product has 2 mole of CO. So product has more entropy

(B) Reactant has gaseous substance while product has only solid substance. So in this case entropy of system will decrease.

(C) One mole of gaseous reactant gives 2 mole of gaseous product. Hence entropy increase.

(D) Reactant is solid while product ions in aqueous phase so product has more entropy.

(E) 2 moles of reactant gas gives total 4 mole of product gas. so product has more entropy than reactant

queen_honey_blossom answered 2 years ago
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