In: Statistics and Probability
In exercise 12, the following data on x = average daily hotel room rate and y = amount spent on entertainment (The Wall Street Journal, August 18, 2011) lead to the estimated regression equation ŷ = 17.49 + 1.0334x. For these data SSE = 1541.4. Click on the webfile logo to reference the data. a. Predict the amount spent on entertainment
for a particular city that has a daily room rate of $89 (to 2
decimals). b. Develop a 95% confidence interval for the
mean amount spent on entertainment for all cities that have a daily
room rate of $89 (to 2 decimals). c. The average room rate in Chicago is $128.
Develop a 95% prediction interval for the amount spent on
entertainment in Chicago (to 2 decimals). |
Icon Key
Question 7 of 10
Exercise 12.39
a). 109.46
b). 95% CI= (94.85, 124.08)
c). 95% PI = (110.69, 188.84)
Regression Analysis |
||||||
r² |
0.740 |
n |
9 |
|||
r |
0.860 |
k |
1 |
|||
Std. Error |
14.839 |
Dep. Var. |
Entertainment |
|||
ANOVA table |
||||||
Source |
SS |
df |
MS |
F |
p-value |
|
Regression |
4,378.5778 |
1 |
4,378.5778 |
19.88 |
.0029 |
|
Residual |
1,541.4222 |
7 |
220.2032 |
|||
Total |
5,920.0000 |
8 |
||||
Regression output |
confidence interval |
|||||
variables |
coefficients |
std. error |
t (df=7) |
p-value |
95% lower |
95% upper |
Intercept |
17.4915 |
24.8314 |
0.704 |
.5039 |
-41.2255 |
76.2084 |
Roomrate |
1.0334 |
0.2318 |
4.459 |
.0029 |
0.4854 |
1.5814 |
Predicted values for: Entertainment |
||||||
95% Confidence Intervals |
95% Prediction Intervals |
|||||
Roomrate |
Predicted |
lower |
upper |
lower |
upper |
Leverage |
89 |
109.465 |
94.847 |
124.083 |
71.453 |
147.478 |
0.174 |
128 |
149.769 |
132.574 |
166.964 |
110.693 |
188.844 |
0.240 |
NOTE:: I HOPE YOUR HAPPY WITH MY ANSWER....***PLEASE SUPPORT ME WITH YOUR RATING...
***PLEASE GIVE ME "LIKE"...ITS VERY IMPORTANT FOR ME NOW....PLEASE SUPPORT ME ....THANK YOU