Question

In: Mechanical Engineering

In the rolling lab we measured the following conditions: R = 32.25; % roller radius (mm)...

In the rolling lab we measured the following conditions:

R = 32.25; % roller radius (mm)

Nr = 30; % roll rotational speed in rpm

A 8-pass flat rolling process was performed with one set of workpiece dimensional data of length l, width w, and thickness t, measured as below:

(with the first set of data for initial solder wire, and the rests are the outlet dimensions of each pass)

l = [37.85 39.55 41.39 45.96 50.19 59.83 79.64 127.5 260.0]; %length (mm)

w = [2.92 3.22 3.51 3.63 3.76 4.02 4.21 4.30 4.35]; %width (mm)

h = [2.92 2.38 2.059 1.672 1.470 1.126 0.802 0.468 0.177]; %thickness (mm)

The total rolling time for each pass is:

t = [0.35 0.39 0.44 0.48 0.58 0.78 1.25 2.55];

Express the x-component of the velocities of the roll vr(x) and the workpiece metal vm(x) as a function of x (where x is in rolling direction and x=0 at the outlet section), for each pass, and plot vr(x) and vm(x) for each pass in one figure

Solutions

Expert Solution

Roller Radius R =32.25 mm
speed N = 30 rpm
Circumference of roller = PI*2*R = 202.63 mm
Since we need to focus on X dircetion only, we will consider only length of workpiece for graph.
Assuming given time in Seconds.
Roller Velocity = Circumference/Time

Workpiece Velocity = Length/Time

Time (Second)
Roller Velocity (Vrx)
workpiece velocity (Vmx)
0.35 578.94 113
0.39 519.56 106.12
0.44 460.52 104.45
0.48 422.14 104.56
0.58 349.36 103.15
0.78 259.78 102.10
1.25 162.104 102
2.55 79.46 101.96


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