In: Statistics and Probability
. Assume X ~ N (10, 4).
Given
i. The approximate distribution of sample mean \bar{X} if the
sample size n = 100,
is Normally distributed
According the Central Limit Theorem, consider an iid sample
Then as the sample size increases, the sample mean converges in
distribution to a standard normal
So the approximate distribution of \bar{X} for a sample size n is
In our case with
ii. As sample size increases, the variance of \bar{X} decreases
So as sample size n increases, variance decreases
Here is the sampling distribution of \bar{X} as a function of
n,
You can see in the plot below that the curve becomes less wider as
n increases,
hence the variance decreases
iii) The two values (symmetric around the population mean) that
contain
of the population can be derived as follows:
Let L and U be the standardized lower and upper bounds of the interval, then as it is a symmetric interval,
\implies
(This is the symmetric interval)
The plot of the symmetric interval is given below
Hence for
a) 75% interval,
Now the interval is given by,
In our case with
a) 95% interval,
Now the interval is given by,
In our case with