Assuming the population has an approximate normal distribution, if a sample size n=10 has a sample...

Assuming the population has an approximate normal distribution, if a sample size n=10 has a sample mean ¯x=36 with a sample standard deviation s=9, find the margin of error at a 90% confidence level. THEN YOU MUST ROUND ANSWER TO TWO DECIMALS PLACES.

Expert Solution

Solution :

Given that,

t /2,df = 1.833

Margin of error = E = t/2,df * (s / $\sqrt$ n)

= 1.833 * (9 / $\sqrt$ 10)

Margin of error = E = 5.22

The 90% confidence interval estimate of the population mean is,

- E < < + E

36 - 5.22 < < 36 + 5.22

30.78 < < 41.22

(30.78 , 41.22)

orchestra answered 2 years ago

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