Question

A random sample of 53 individuals shows an average income of $54,083 per year. We know from previous research that the standard deviation for income is 24,470. I hypothesis that the true population mean for income is $51,085 per year. What is the z-statistic for this hypothesis?

Round your answer to four decimal places.

Answer 1

this is the two tailed test .  

The null and alternative hypothesis is ,

H0 :   = 51,085

Ha :     51,085

Test statistic = z

= ( - ) / / n

= (54083-51085) / 24,470 / 53

= 0.8919

P(z > ) = 1 - P(z < ) =

P-value =

= 0.05  

P-value <

Reject the null hypothesis .