In: Physics
Using laplace transformations, find the charge and current of an LRC circuit in series where L=1/2h, R=10ohm, C=1/50f, E(t)=300V, q(0)=0C, i(0)=0A. ( Lq'' + Rq' + (1/C)q = E(t) ). The answer is q(t) = 10 - (10e^-3t)cos(3t) - (10e^-3t)sin(3t) and i(t) = (60e^-3t)sin(3t).