In: Statistics and Probability
Suppose that a population is known to be normally distributed with µ = 317 and σ = 90. If a random sample of size n = 50 is selected, calculate the probability that the sample mean is greater than 300.
Solution :
Given that,
mean = = 317
standard deviation = = 90
= =317
= / n = 90 / 50 = 12.73
P( >300 ) = 1 - P( < 300)
= 1 - P[( - ) / < (300-317) /12.73 ]
= 1 - P(z <-1.34 )
Using z table
= 1 - 0.0901
=0.9099