In: Statistics and Probability
A particular fruit's weights are normally distributed, with a mean of 652 grams and a standard deviation of 22 grams. If you pick 7 fruit at random, what is the probability that their mean weight will be between 624 grams and 637 grams
Solution :
Given that ,
mean =
= 652
standard deviation =
= 22
n = 7
= 652
=
/
n= 22 /
7=8.3
P(624<
<637 ) = P[(624-652) /8.3 < (
-
) /
< (637-652) /8.3 )]
= P(-3.37 < Z <-1.81 )
= P(Z <-1.81 ) - P(Z < -3.37)
Using z table
=0.0351 - 0.0004
=0.0347
probability= 0.0347