Answer:
No, they cannot share the same address because they have
different addresses from one another.
Explanation:
Scenario:
- The circuit is a completely functioning Microprocessor where is
developed by the combination of numerous circuits. We control what
we need the processor to do by allocating an incentive from 0 – 15
in the FCN of our ALU.
- Next, we need to allocate a location for our 3x8
Decoder to peruse data from (or compose data). These addresses are
alluded to as ROM 0, ROM 1, ROM 2, ROM 3. These addresses
can compose data constrained by the client. For example, if we put
a 2 in address 0 and a 1 in address 1, we can peruse this data and
play out whatever function we'd like with it, at that point store
this data in different addresses determined (WOM 0, WOM 1, RAM 6,
RAM 7).
- So beginning from the earliest starting point, we need our
CLEAR ACCUM and ALU REG high (1) since it is active low.
- Next, we can appoint a function we need to do, similar to
isolate or NOT A or something. After completion of doing this,
ensure we have the data we need in the best possible addresses we
read from (ROM addresses).
Result:
ROM 0 and ROM 1 share an address with WOM 0 and WOM 1,
separately. In any case, ROM 3 and 4 can't and don't share an
address with RAM 6 and 7. This because they basically have
unexpected addresses in comparison to each other. If we set the 3x8
Decoder to a location that is intended to understand data and not,
nothing will occur.
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