In: Statistics and Probability
For a particular chemical synthesis, the effect of precursor concentration and catalyst amount were studied.
Catalyst amount 0.5 kG |
Catalyst amound 1 kG |
|
Precursor concentration 15% |
17, 18, 21 |
31, 28, 29 |
Precursor concentration 30% |
28, 24, 27 |
34, 37, 41 |
Calculate the : a)effect of each factor and interaction between factors, b)significance of each factor and interactions, c) residuals between the actual value and the linear statistical model based on the estimates from 1. Do you think the residuals are normally distributed.
Source | SS | df | MS | F | p-value |
Factor 1 | 184.08 | 1 | 184.083 | 31.56 | .0005 |
Factor 2 | 352.08 | 1 | 352.083 | 60.36 | .0001 |
Interaction | 0.08 | 1 | 0.083 | 0.01 | .9078 |
Error | 46.67 | 8 | 5.833 | ||
Total | 582.92 | 11 |
The hypothesis being tested is:
H0: There is no main effect of Precursor concentration
Ha: There is a main effect of Precursor concentration
The p-value is 0.0005.
Since the p-value (0.0005) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that there is a main effect of Precursor concentration.
The hypothesis being tested is:
H0: There is no main effect of Catalyst amount
Ha: There is a main effect of Catalyst amount
The p-value is 0.0001.
Since the p-value (0.0001) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that there is a main effect of the Catalyst amount.
The hypothesis being tested is:
H0: There is no interaction effect of Catalyst amount and Precursor concentration
Ha: There is an interaction effect of Catalyst amount and Precursor concentration
The p-value is 0.9078.
Since the p-value (0.9078) is greater than the significance level (0.05), we cannot reject the null hypothesis.
Therefore, we cannot conclude that there is an interaction effect of Catalyst amount and Precursor concentration.
The residuals are:
RESI
-1.66667
-0.66667
2.33333
1.66667
-2.33333
0.66667
-0.00000
-0.00000
0.00000
0.00000
0.00000
0.00000
Yes, the residuals are normally distributed.
Please give me a thumbs-up if this helps you out. Thank you!