The proportion of the standard normal curve that falls between the mean and a Z-score of...

The proportion of the standard normal curve that falls between the mean and a Z-score of 2.15 is .4842.

true or false

Expert Solution

TRUE

µ =    0
σ =    1
we need to calculate probability for ,
P (   0   < X <   2.15   )
=P( (0-0)/1 < (X-µ)/σ < (2.15-0)/1 )

P (    0.000   < Z <    2.150   )
= P ( Z <    2.150   ) - P ( Z <   0.000   ) =    0.9842   -    0.5000   =    0.4842

Please revert back in case of any doubt.

Please upvote. Thanks in advance.

orchestra answered 2 years ago

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The proportion of the standard normal curve that falls between the mean and a Z-score of...

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