In: Statistics and Probability
Can you explain step by step for me? "Dumb it down"? I need a lot of help with this question. Thank you so much!
This is the sample set. The s ample mean is 100 and the SD is 10 and the s ample size is 400.
Construct the 95% confidence interval?
Solution :
Given that,
Point estimate = sample mean =
= 100
Population standard deviation =
= 10
Sample size n =400
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table )
Margin of error = E = Z/2
* (
/n)
= 1.96 * ( 10 / 400
)
E= 0.98
At 95% confidence interval estimate of the population mean
is,
- E <
<
+ E
100- 0.98<
<100 + 0.98
99.02 <
< 100.98
( 99.02 , 100.98 )