In: Statistics and Probability
MY NOTES
How much do wild mountain lions weigh? Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains gave the following weights (pounds):
71 | 102 | 126 | 123 | 60 | 64 |
Assume that the population of x values has an approximately normal distribution.(a) Use a calculator with mean and sample standard deviation keys to find the sample mean weight x and sample standard deviation s. (Round your answers to one decimal place.)
x = | lb |
s = | lb |
(b) Find a 75% confidence interval for the population average
weight μ of all adult mountain lions in the specified
region. (Round your answers to one decimal place.)
lower limit | lb |
upper limit | lb |
Solution:
x | x2 |
71 | 5041 |
102 | 10404 |
126 | 15876 |
123 | 15129 |
60 | 3600 |
64 | 4096 |
∑x=546 | ∑x2=54146 |
Mean ˉx=∑xn
=71+102+126+123+60+646
=5466
=91
Sample Standard deviation S=√∑x2-(∑x)2nn-1
=√54146-(546)265
=√54146-496865
=√44605
=√892
=29.8664
Degrees of freedom = df = n - 1 = 6 - 1 = 5
At 75% confidence level the t is ,
= 1 - 75% = 1 - 0.75 = 0.25
/ 2 = 0.25 / 2 = 0.125
t /2,df = t0.0.125,5 =1.301
Margin of error = E = t/2,df * (s /n)
= 1.301 * (29.87 / 6)
= 15.86
Margin of error = 15.86
The 75% confidence interval estimate of the population mean is,
- E < < + E
91 - 15.86 < < 91 + 15.86
75.14 < < 106.86
Lower limit =75.14
Upper limit =106.86