Question

Determine the outputs of the code:

String[]array= {"Namath","Sauer","Namath","Namath","Snell","Snell","Namath","Namath","Namath", "Maynard","Namath","Namath"};
       ArrayList<String>list=new ArrayList<String>();
       for(int i=0;i<array.length;i++)
       {
           list.add(array[i]);
       }
       System.out.println("OUTPUT 1");
       System.out.println(list);
       System.out.println("OUTPUT 2");
       for(int i=0;i<list.size();i++)
       {
           if(list.get(i).equals("Namath"))
           {
               System.out.println(i+"\t"+ list.remove(i));
           }
       }
       System.out.println("OUTPUT 3");
       for(String s:list)
       {
           System.out.println(s);
       }
      
  

/*
OUTPUT 1

OUTPUT 2

OUTPUT 3

*/

Answer 1

ANSWER: Here I am giving you the code and output. The explanation is given in the code as a comment.

CODE:

import java.util.*;
public class Main
{
   public static void main(String[] args) {
       String[]array= {"Namath","Sauer","Namath","Namath","Snell","Snell","Namath","Namath","Namath", "Maynard","Namath","Namath"};
ArrayList<String>list=new ArrayList<String>();
for(int i=0;i<array.length;i++)
{
list.add(array[i]);
}
System.out.println("OUTPUT 1");// In output here its simply printing the list items
System.out.println(list);
System.out.println("OUTPUT 2");// In output2 if the list items is equal to the Namath then it is removing it from the list and printing at which index it is available.
for(int i=0;i<list.size();i++)
{
if(list.get(i).equals("Namath"))
{
System.out.println(i+"\t"+ list.remove(i));
}
}
System.out.println("OUTPUT 3"); // In this OUTPUT3 remaining list items will be printed after removing Namath.
for(String s:list)
{
System.out.println(s);
}
   }
}

OUTPUT: