Question

In: Chemistry

In order to make 25 mL of an 80 ppm solution, what volume of the 1000...

In order to make 25 mL of an 80 ppm solution, what volume of the 1000 ppm solution would be needed?

Solutions

Expert Solution

80ppm

1ppm   = 1mg/L

80PPm = 80mg/L

1000ppm = 1000mg/L

intial                                                                                  final

M1 = 80mg/L                                                                 M2 = 1000mg/L

V1   = 25ml                                                                      V2 =

              M1V1   = M2V2

               V2     =   M1V1/M2

                        = 80*25/1000   = 2ml >>>>answer


Related Solutions

A solution with a final volume of 500 mL was prepared by dissolving 25 mL of...
A solution with a final volume of 500 mL was prepared by dissolving 25 mL of methanol {CH2OH} (density = 0.7914) in chloroform {CHCl3}. Calculate its molar concentration. (MWMethanol = 32.00) (show the solution)
What volume of a 0.1 M NaOH solution must be combined with 25 mL of 0.2...
What volume of a 0.1 M NaOH solution must be combined with 25 mL of 0.2 M HNO3 to reach a pH of 11.5?
A solution consists of 35 ppm of benzene. The density of the solution is 1.00g/mL. How...
A solution consists of 35 ppm of benzene. The density of the solution is 1.00g/mL. How many grams of benzene are in 1 g of solution? How many grams of benzene are in 1.0 L of the solution? What is the mass percentage of benzene in the solution? Please show calculations!
1. Calculate the volume in milliliters (mL) of a 6.00 M NaOH solution needed to make...
1. Calculate the volume in milliliters (mL) of a 6.00 M NaOH solution needed to make 5.00 x 102 mL of a 0.100 M NaOH solution. (Recall that M = molar = mol/L, and show all your work). 2. An approximately 0.1 M NaOH solution was standardized with KHP by titration to a phenolphthalein endpoint. From the following data, calculate the average molarity of the NaOH. The molar mass of KHP is 204.22 g/mol. Trial 1 Trial 2 Mass of...
Molarity of NaOH solution: .25 M 1. Trial Titration Final buret volume (mL): 34.4 mL Initial...
Molarity of NaOH solution: .25 M 1. Trial Titration Final buret volume (mL): 34.4 mL Initial Buret Volume (mL): 0mL Volume of NaOH solution (mL): 34.4 mL 2. Exact titration Sample no. 1 2 3 4 Final buret volume (mL)36.1, 34.9, 34.2, 46.2 intial buret buret volume (mL) 0, 0, 0, 12 Volume of NaOH solution (mL) 36.1, 34.9, 34.2, 34.2 concentration of HC2H3O2 (M) ________ ________ _________ _________ Mean Concentration (M) ________ ________ _________ _________ Show Calculations: Questions: 1.The...
To what volume (in mL) should 8.25 mL of an 6.5 M acetic acid solution be...
To what volume (in mL) should 8.25 mL of an 6.5 M acetic acid solution be diluted in order to obtain a final solution that is 2 M?
a) What volume (in mL) of 8.84 M HBr would be required to make 300.0 mL...
a) What volume (in mL) of 8.84 M HBr would be required to make 300.0 mL of a solution with a pH of 2.61? b) An unknown weak base with a concentration of 0.0910 M has a pH of 11.70. What is the Kb of this base? c) What is the pH of a 0.500 M solution of HF (Ka = 6.8 × 10⁻⁴) d) A diprotic acid, H₂A, has Ka1 = 3.4 × 10⁻⁴ and Ka2 = 6.7 ×...
A 5.00-mL aliquot of a solution that contains 3.57 ppm Ni2+ is treated with an appropriate...
A 5.00-mL aliquot of a solution that contains 3.57 ppm Ni2+ is treated with an appropriate excess of 2,3-quinoxalinedithiol and diluted to 50.0 mL. The molar absorptivity of a Ni2+- 2,3-quinoxalinedithiol solution at 510 nm is 5520 L mol-1 cm-1. What is the absorbance of the above diluted Ni2+- 2,3-quinoxalinedithiol solution at 510 nm in a 2.00-cm cell?
Calculate the molarity of an HCl solution if a volume of 39.54 mL of this solution...
Calculate the molarity of an HCl solution if a volume of 39.54 mL of this solution is required to titrate 0.2348 g Na2CO3. (Bromocresol green is used as an indicator). This HCl solution (calculated in question 1.) is then used to analyze an unknown sample. Calculate the % Na2CO3 in the sample if a volume of 23.44 mL of the HCl solution is required to titrate 0.4089 g of the sample
To what volume (in mL) should you dilute 100.0 mL of a 5.00 M CaC2 solution...
To what volume (in mL) should you dilute 100.0 mL of a 5.00 M CaC2 solution to obtain a 0.750 M CaC2 solution?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT