If n=110 and ˆpp^ (p-hat) =0.43, find the margin of error at a 90% confidence level...

If n=110 and ˆpp^ (p-hat) =0.43, find the margin of error at a 90% confidence level

Give your answer to three decimals.

Solutions

Expert Solution

SOLUTION

Point estimate = sample proportion = = 0.43

1 - =0.57

At 90% confidence level

= 1 - 90%

= 1 - 0.90 =0.10

/2 = 0.05

Z/2 = Z0.05 = 1.645 ( Using z table )

Margin of error = E Z/2 * $\sqrt$ (( * (1 - )) / n)

= 1.645 * $\sqrt$ ((0.43*0.57) / 110)=0.078

orchestra answered 1 year ago

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