If n=210 and ˆp(p-hat) =0.4, find the margin of error at a 95% confidence level Give...

If n=210 and ˆp(p-hat) =0.4, find the margin of error at a 95% confidence level

Give your answer to three decimals

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Expert Solution

Solution :

Given that,

n = 210

Point estimate = sample proportion = =0.4

1 - = 1-0.4 =0.6

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96 ( Using z table )

Margin of error = E = Z/2 * $\sqrt$ ((( * (1 - )) / n)

= 1.96 ( $\sqrt$ ((0.4*0.6) / 210)

E = 0.066

orchestra answered 1 year ago

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