Given that,
Point estimate = sample proportion =
=0.7
1 -
= 1-0.7 =0.3
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z
/2
= Z 0.05 = 1.645 ( Using z table )
Margin of error = E Z
/2
*
((
* (1 -
)) / n)
= 1.645 *
((0.7*0.3)
/540 )
E = 0.032
A 90% confidence interval for population proportion p is ,
- E < p <
+ E
0.7 - 0.032 < p < 0.7+0.032
_0.668 < p < _0.732___