Question

A kinesiologist wanted to investigate the effect of temperature and humidity on human performance. He found 28 college students and randomly assigned them to four different conditions, during which they were to walk at their normal pace on a treadmill for 60 minutes. He measured how far, in miles, they walked. The conditions varied in temperature (normal temperature/high temperature) and humidity (normal humidity/high humidity). The data are presented below, and SSwithin = 1.58. Do all hypothesis testing steps and compute effect sizes. Note that T = Σx.  

Normal Temperature, Normal Humidity

n = 7

M = 3.00

T = 21

Normal Temperature, High Humidity

n = 7

M = 2.80

T = 19.60

High Temperature, Normal Humidity

n = 7

M = 2.80

T = 19.60

High Temperature, High Humidity

n = 7

M = 2.00

T = 14

Answer 1

Normal Temperature, Normal Humidity=x1

Normal Temperature, High Humidity=x2

High Temperature, Normal Humidity=x3

High Temperature, High Humidity=x4

x1	x2	x3	x4
n1 = 7	n2 = 7	n3 = 7	n4 = 7
M1 = 3.00	M2 = 2.80	M3 = 2.80	M4 = 2.00
T1 = 21	T2 = 19.60	T3 = 19.60	T4 = 14

Here we solve this problem by one-way-ANOVA method,

Hypothesis:

Ho: There is no significant difference in means of these groups.

V/s

H1: There is significant difference in means of these groups.

Under Ho,

SSe=SSwithin=1.58 is given

#consider alpha=0.05

Here F < at 0.05 then we fail to reject Ho.There is no significant difference in means of these groups.

We have to compute the effect size,