Question

In: Statistics and Probability

1 7 0.406 2 14 2.731 3 13 3.807 4 10 1.999 5 14 1.884 6...

1

7

0.406

2

14

2.731

3

13

3.807

4

10

1.999

5

14

1.884

6

15

2.275

7

17

4

8

13

2.597

9

4

0

10

11

2.651

11

6

0

12

11

1.558

13

13

3.147

14

12

3.378

15

15

3.127

16

10

1.989

17

11

2.183

18

13

2.178

19

11

3.132

20

10

1.445

21

9

0.841

22

18

2.825

23

10

2.036

24

12

1.601

25

13

2.835

26

11

1.162

27

7

1.677

28

7

0.423

29

16

4.018

30

11

1.742

31

19

3.876

32

16

3.578

10. What is the estimated increase in number of fatal accidents per 1000 licenses due to a 1% increase in the percentage of drivers under 21 (ie. the slope)?

11. What is the standard deviation of the estimated slope?

12. What is the estimated number of fatal accidents per 1000 licenses if there were no drivers under the age of 21 (ie. the intercept)?

Solutions

Expert Solution

The important thing here is to decide the dependent and independent variables. Since we are interested in finding whether the number of fatal accidents is dependent on the percentage of drivers that are under 21.

So, the percentage of driver that is under 21 is the dependent variable. Now, all we have to do is plotting the data in Excel and doing the regression.

So, in excel, I have chosen x as % of driver under 21 and y as number of fatal accidents per 100 licenses and select linear regression.

I get the following output

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.835631
R Square 0.69828
Adjusted R Square 0.688223
Standard Error 0.636578
Observations 32
ANOVA
df SS MS F Significance F
Regression 1 28.13522582 28.13522582 69.4299 2.66759E-09
Residual 30 12.1569629 0.405232097
Total 31 40.29218872
Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0%
Intercept -1.00839 0.403678923 -2.498010322 0.0182 -1.832816463 -0.18397 -1.83282 -0.183971771
X Variable 1 0.272743 0.032732592 8.332460897 2.67E-09 0.205894169 0.339592 0.205894 0.339591909

10)

The equation is Fatal accidents/1000 licensed = -1.00839 + 0.272743 % drivers under 21

So, slope is 0.272743

11) Standard deviation of the slope is 0.032732592

12) Intercept = -1.00839

I have highlighted the answers from the table


Related Solutions

Match No. 1 2 3 4 5 6 7 8 9 10 11 12 13 14...
Match No. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Player A 8 42 56 68 91 123 12 46 57 137 5 80 14 10 19 Player B 38 44 46 59 57 61 48 42 51 39 58 41 55 45 68 1. For the given data set representing the runs scored by two players in last 15 matches, conduct the following analysis: i. Which average you will use to summarize...
Day 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15...
Day 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Number of Aides Absent 5 8 11 15 4 2 7 1 4 6 14 19 3 5 8 In which of the following ranges you can find the Upper Control Limit of the control chart? 0.1427 0.1536 0.1677 Not computable with information available In which of the following ranges you can find the Lower Control Limit of the control chart? Does not exit...
student 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15...
student 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Test score 67 67 87 89 87 77 73 74 68 72 58 98 98 70 77 Above we have the final averages of the last stats and I want to know if the class average falls within the boundaries of all my statistics classes for the past 20 years. Find the sample size, mean, and standard deviation of the data above (Table 1)....
x 3, 4, 5, 7, 8 y 3, 7, 6, 13, 14 (a) Find the estimates...
x 3, 4, 5, 7, 8 y 3, 7, 6, 13, 14 (a) Find the estimates of Bo and B1. Bo=bo= _____ (Round to three decimal places as needed.) B1=b1= ______(Round to four decimal places as needed.) (b) Compute the standard error the point estimate for se= ____ (c) Assuming the residuals are normally distributed, determine Sb1=____ (Round to four decimal places as needed.) (d) Assuming the residuals are normally distributed, test HoB1=0 versus H1:B1/=0 at the a=0.05 level of...
Consider the data. xi 1 2 3 4 5 yi 3 7 5 10 13 (a)...
Consider the data. xi 1 2 3 4 5 yi 3 7 5 10 13 (a) Compute the mean square error using equation s2 = MSE = SSE n − 2  . (Round your answer to two decimal places.) (b) Compute the standard error of the estimate using equation s = MSE = SSE n − 2  . (Round your answer to three decimal places.) (c) Compute the estimated standard deviation of b1 using equation sb1 = s Σ(xi −...
Periods ​1% ​2% ​3% ​4% ​5% ​6% ​7% ​8% ​9% ​10% ​12% ​14% ​15% ​16% ​18%...
Periods ​1% ​2% ​3% ​4% ​5% ​6% ​7% ​8% ​9% ​10% ​12% ​14% ​15% ​16% ​18% ​20% 1 0.990 0.980 0.971 0.962 0.952 0.943 0.935 0.926 0.917 0.909 0.893 0.877 0.870 0.862 0.847 0.833 2 0.980 0.961 0.943 0.925 0.907 0.890 0.873 0.857 0.842 0.826 0.797 0.769 0.756 0.743 0.718 0.694 3 0.971 0.942 0.915 0.889 0.864 0.840 0.816 0.794 0.772 0.751 0.712 0.675 0.658 0.641 0.609 0.579 4 0.961 0.924 0.888 0.855 0.823 0.792 0.763 0.735 0.708 0.683 0.636...
Post Position 1 2 3 4 5 6 7 8 9 10 Wins 19 14 11...
Post Position 1 2 3 4 5 6 7 8 9 10 Wins 19 14 11 15 15 7 8 12 5 11 The table below lists the frequency of wins for different post positions in the Kentucky Derby horse race. Use a 0.05 significance level to test the claim that the likelihood of winning is the same for the different post positions. What is the critical value (the X2 value)? [Round to the nearest thousandths place]
ID X Y 1 2 3 2 3 6 3 4 6 4 5 7 5...
ID X Y 1 2 3 2 3 6 3 4 6 4 5 7 5 8 7 6 5 7 7 6 7 8 8 8 9 7 8 10 12 11 Test the significance of the correlation coefficient. Then use math test scores (X) to predict physics test scores (Y).  Do the following: Create a scatterplot of X and Y. Write the regression equation and interpret the regression coefficients (i.e., intercept and slope). Predict the physics score for each....
[4 5 5 2 4 4 6 3 3 7 5 3 6 3 4 4...
[4 5 5 2 4 4 6 3 3 7 5 3 6 3 4 4 6 5 4 5 3 7 5 5 4 2 6 5 6 6] This is my dataset Find mean, median, mode, variance, standard deviation, coefficient of variation, range, 70th percentile, 3rdquartile of the data and skewness and define what each of these statistics measure. For example, mean is a measure of the central tendency, what about the rest? Use Chebyshev’s rule to find...
[4 5 5 2 4 4 6 3 3 7 5 3 6 3 4 4...
[4 5 5 2 4 4 6 3 3 7 5 3 6 3 4 4 6 5 4 5 3 7 5 5 4 2 6 5 6 6] This is my dataset Split the dataset in two equal parts. You have 30 datavalues. If you split the data in two equal parts each part will contain 15 data values.  Call the first part Y and second part X.Draw scatter plot of the 2 datasets, X being on the horizontal...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT