Question

In: Statistics and Probability

Post Position 1 2 3 4 5 6 7 8 9 10 Wins 19 14 11...

Post Position 1 2 3 4 5 6 7 8 9 10
Wins 19 14 11 15 15 7 8 12 5 11

The table below lists the frequency of wins for different post positions in the Kentucky Derby horse race.

Use a 0.05 significance level to test the claim that the likelihood of winning is the same for the different post positions.

What is the critical value (the X2 value)? [Round to the nearest thousandths place]

Solutions

Expert Solution

total frequency=   117
expected frequncy,E = expected proportions*total frequency  

observed frequencey, O expected proportion expected frequency,E (O-E) (O-E)²/E
19 0.100 11.70 7.30 4.555
14 0.100 11.70 2.30 0.452
11 0.100 11.70 -0.70 0.042
15 0.100 11.70 3.30 0.931
15 0.100 11.70 3.30 0.931
7 0.100 11.700 -4.70 1.888
8 0.100 11.700 -3.70 1.170
12 0.100 11.700 0.30 0.008
5 0.100 11.700 -6.70 3.837
11 0.100 11.700 -0.70 0.042

chi square test statistic,X² = Σ(O-E)²/E =   13.855              
                  

level of significance, α=   0.05              
Degree of freedom=k-1=   10   -   1   =   9
                                
Critical value =    16.919   [ Excel function: =chisq.inv.rt(α,df) ]          
Decision: test stat < critical  , Do not reject Ho                  


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