In: Statistics and Probability
A cyclist won a bicycle race for seven consecutive years. His "winning" times and "victory" margins (time difference of the second place finisher) are given in the figure below.
Year | Time (h:m:s) |
Margin (m:s) |
---|---|---|
1999 | 91:32:19 | 7:35 |
2000 | 92:33:07 | 6:07 |
2001 | 86:17:27 | 6:41 |
2002 | 82:05:12 | 7:18 |
2003 | 83:41:12 | 1:05 |
2004 | 83:36:05 | 6:13 |
2005 | 86:15:05 | 4:20 |
(a) Find the mean, median and mode of the cyclist's times. (If an answer does not exist, enter DNE.)
mean | : : h:m:s |
median | : : h:m:s |
mode | : : h:m:s |
(b) Find the mean, median and mode of the cyclist's margins. (If an
answer does not exist, enter DNE.)
mean | : m:s |
median | : m:s |
mode | : m:s |
Solution:-
We have given data as follows.
Year |
Time (H:M:S) |
Margin (M:S) |
---|---|---|
1999 | 91:32:19 | 7:35 |
2000 | 92:33:07 | 6:07 |
2001 | 86:17:27 | 6:41 |
2002 | 82:05:12 | 7:18 |
2003 | 83:41:12 | 1:05 |
2004 | 83:36:05 | 6:13 |
2005 | 86:15:05 | 4:20 |
Now we have to convert data (H:M:S) in Only Hours
Ex: 34:30:00
Formula:-
Therefore,
34:30:00 = 34.5 hours
And
We have to convert data (M:S) in only minutes
Ex: 4:15
Formula:-
Therefore,
4:15 = 4.25 minutes
Therefore above data can be written as,
Year |
Time (H) |
Margin (M) |
---|---|---|
1999 | 91.5386 | 7.58 |
2000 | 92.5519 | 6.12 |
2001 | 86.2908 | 6.68 |
2002 | 82.0867 | 7.30 |
2003 | 83.6867 | 1.08 |
2004 | 83.6014 | 6.22 |
2005 | 86.2514 | 4.33 |
Total | 606.0075 | 39.31 |
a) Find mean median and mode for cyclists time:-
----->
#)mean:-
Mean= Sum (time)/Total no.of observation(n)
Mean=606.0075/7
Mean=86.5725 hours.
Mean=86:34:21 .....in(H:M:S) units
#)Median:-
Median =[ (n+1)/2]th observation ..(after data in ascending order)
...............n=total no. of observation =7
Median=[(7+1)/2]th observation
Median= 4th observation
Here, 86.2514 is the 4 th observation after data in ascending order
Therefore,
Median= 86.2514 hours.
Median =86:15:05.....in(H:M:S) units
#mode:-
Mode= mode is the value in data set which occurs frequently (more than one times)
From above dataset, there is no observation which occurs frequently.
Therefore,
Mode Doesn't exist.
Mode=DNE
b)find mean median and mode for cyclists margin.
----->
#mean:-
Mean= Sum (margin)/Total no.of observation(n)
Mean=39.31/7
Mean=5.6157 minutes.
Mean=05:37 .....in(M:S) units
#)Median:-
Median =[ (n+1)/2]th observation ..(after data in ascending order)
...............n=total no. of observation =7
Median=[(7+1)/2]th observation
Median= 4th observation
Here, 6.12 is the 4 th observation after data in ascending order
Therefore,
Median= 6.12 minutes.
Median =06:07....in(M:S) units
#mode:-
Mode= mode is the value in data set which occurs frequently (more than one times)
From above dataset, there is no observation which occurs frequently.
Therefore,
Mode Doesn't exist.
Mode=DNE
Result:-
Result:- | Time(H:M:S) | Margin(M:S) |
---|---|---|
Mean | 86:34:21 | 05:37 |
Median | 86:15:05 | 06:07 |
Mode | DNE | DNE |