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The present age of a person is double the age of his son. Ten years ago, his age was four times the age of his son. Use the concept of algebra and find the present age of the son.

The present age of a person is double the age of his son. Ten years ago, his age was four times the age of his son. Use the concept of algebra and find the present age of the son.

Solutions

Expert Solution

Let us consider the present age of the son as 'x' years. It is given that the age of the person is double the age of his son, so the age of the person is '2x' years. Now considering the situation 10 years ago, the age of the son was (x - 10) years and the age of the person was (2x - 10) years. The question says that 10 years ago the age of the person was 4 times the age of his son. Therefore, this can be expressed as,

2x - 10 = 4(x - 10)

2x - 10 = 4x - 40

2x - 4x = -40 + 10

-2x = -30

2x = 30

x = 30/2

x = 15

Therefore, the present age of the son is 15 years.

 

 

15years

Nipun Maity answered 2 years ago
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