A balloon filled with 2.00 L of helium initially at 1.25 atm of pressure rises into...

A balloon filled with 2.00 L of helium initially at 1.25 atm of pressure rises into the atmosphere. When the surrounding pressure reaches 330. mmHg, the balloon will burst. If 1 atm = 760. mmHg, what volume will the balloon occupy in the instant before it bursts?

Expert Solution

Initial final

V1 = 2L V2 =

P1 = 1.25atm P2 = 300/760 = 0.3947atm

P1V1 = P2V2

V2 = P1V1/P2

= 1.25*2/0.3947 = 6.34L

The volume of balloon = 6.34L

queen_honey_blossom answered 2 years ago

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